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Representation of Cell

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Question

Calculate reduction potential of the following half-cell reaction at 25 $^{\circ} C$ .

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Solution

$2 H_{2} O + 2 e^{-} \to H_{2} + 2 O H^{-}$
$E = E^{0} - \frac{0.0591}{2}$ $log {[{O H}^{-}]}^{2} [p_{H_{2}}]$
$= 0 - \frac{0.0591}{2} log {(10^{- 7})}^{2} (1)$ $= 0.4137 v o l t$

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