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Root Mean Square Velocity

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Question

Calculate relative rates of effusion of $S O_{2}$ to $C H_{4}$ , in the mixture obtained by effusing out a mixture with initial molar ratio $\frac{n_{S O_{2}}}{n_{C H_{4}}} = \frac{8}{1}$ for three effusing steps:

A

2 : 1

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B

1 : 4

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C

1 : 2

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D

None of these

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Solution

The correct option is C $1 : 2$
$\frac{\frac{n_{S O_{2}}}{n_{C H_{4}}}}{81} = (\frac{16}{64})^{3 / 2} = 1$

Therefore, $\frac{r_{S O_{2}}}{r_{C H_{4}}} = \frac{1}{1} \sqrt{\frac{16}{64}} = \frac{1}{2}$

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