Calculate resonance energy of N2O from the following dataHence- H- N2O - 82 kJ mol-1Assume structure N- - N- - OBE of N - N bond - 950 kJ mol-1N - N bond - 420 kJ mol-1O-O bond - 500 kJ mol-1O - N bond - 610 kJ mol-1

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Question

Calculate resonance energy of $N_{2} O$ from the following data
Hence, $△ H^{\circ} (N_{2} O) = 82 k J m o l^{- 1}$
Assume structure $N^{Θ} = N^{⨁} = O$
BE of $(N \equiv N) b o n d = 950 k J m o l^{- 1}$
$(N = N) b o n d = 420 k J$ mol $^{- 1}$
$O = O) b o n d = 500 k J m o l^{- 1}$
$(O = N) b o n d = 610 k J m o l^{- 1}$

- 170 k J m o l^{- 1}

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- 356 k J m o l^{- 1}

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- 88 k J m o l^{- 1}

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- 190 k J m o l^{- 1}

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Similar questions

N_{2} O

△ H^{\circ} (N_{2} O) = 82 k J m o l^{- 1}

N^{Θ} = N^{⨁} = O

(N \equiv N) b o n d = 950 k J m o l^{- 1}

(N = N) b o n d = 420 k J

^{- 1}

O = O) b o n d = 500 k J m o l^{- 1}

(O = N) b o n d = 610 k J m o l^{- 1}

N_{2} O (i n k J m o l^{- 1})

Δ H_{f}^{0}

N_{2} O

82 k J m o l^{- 1}

N \equiv N 946 k J m o l^{- 1}

N = N 418 k J m o l^{- 1}

O = O 498 k J m o l^{- 1}

N = O 607 k J m o l^{- 1}

N_{2} O

Δ H_{f}

N_{2} O = 82 k J {m o l}^{- 1}

N \equiv N

N \equiv N

O \equiv O

N \equiv O

K J {m o l}^{- 1}

N_{2} O

Δ H_{f}^{\circ}

N_{2} O = 82 k J m o l e^{- 1}

N \equiv N

N = N

O = O

N = O

m o l e^{- 1}

N_{2} O (i n k J m o l^{- 1})

Δ H_{f}^{0}

N_{2} O

82 k J m o l^{- 1}

N \equiv N 946 k J m o l^{- 1}

N = N 418 k J m o l^{- 1}

O = O 498 k J m o l^{- 1}

N = O 607 k J m o l^{- 1}

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