Question

Calculate root mean square speed of $O_3$ at $20C$ and 82 cm Hg.

Answer 1

$U_{rms}=\frac{\sqrt{3}\times RT}{M}$

given T=${20}^{0}C$=20+273=293K

R=$8.314\times {10}^7$ erg per degree per mol

$Mof{O}_3$=48

$U_{rm}$=$\frac{\sqrt{3}\times 8.314\times {10}^7\times 293}{48}$

=$3.9\times {10}^4$