Calculate solubility of AgCl in 0.1MNaCl at 25oC if its solubility product at same temperature is 2.0×10−10mol2L−2.
A
2.0×10−7molL−1
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B
2.0×10−9molL−1
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C
2.5×10−7molL−1
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D
3.0×10−9molL−1
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Solution
The correct option is B2.0×10−9molL−1 AgCl and NaCl has univalent cation and anion. We know, In presence of common ion Solubility=KspConcentration of common ion