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Byju's Answer
Standard XII
Chemistry
Solubility Product
Calculate sol...
Question
Calculate solubility of
P
b
I
2
(
K
s
p
=
1.4
×
10
−
8
)
in water at
25
o
C
, which is
90
%
dissociated.
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Solution
Given:-
K
s
p
(
P
b
I
2
)
=
1.4
×
10
−
8
α
=
90
%
P
b
I
2
(
s
)
⇌
P
b
+
2
(
a
q
)
+
2
I
⊝
(
a
q
)
0.9
S
2
×
0.9
S
S
⟶
Solubility
K
s
p
=
0.9
S
(
2
×
0.9
S
)
2
⇒
1.4
×
10
−
8
=
4
(
0.9
)
3
S
3
⇒
S
3
=
1.4
×
10
−
8
4
×
(
0.9
)
3
⇒
S
=
0.78
×
10
−
2
Moles/litre
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Q.
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Q.
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(
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)
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10
−
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