Question

Calculate the accelerating potential that must be imparted to a proton beam to wavelength of 0.005 nm.

Answer 1

Wavelength of protons beam is given by,

$\lambda =\sqrt{\frac{150}{V}}{A}^0$

Where$V$ is accelerating potential

Now $\lambda =0.005nm=0.0005A^0$

$V=\frac{150}{25\times {10}^{-8}}V$

$V=6\times {10}^{8}volt$