Question

Calculate the acceleration due to gravity on the surface of Mars having a mass of $6.4x{10}^{23}$ and a radius of $3.37x{10}^{6}m$.

Answer 1

Step 1 : Given data,

Mass of Mars, $m=6.4x{10}^{23}kg$

Radius of Mars, $R=3.37x{10}^{6}m$

Universal gravitation constant, $G=6.67x{10}^{-11}N{m}^{2}k{g}^{-2}$

Step 2 : Formula used,

Accelertaion due to gravity, $g=\frac{Gxm}{{\left(R\right)}^2}$

Step 3 : Putting values,

$g=\frac{6.67x{10}^{-11}x6.4x{10}^{23}}{{(3.37x{10}^6)}^2}$

$g=\frac{6.67x6.4}{3.37x3.37}x{10}^{-11+\left(23\right)+(-12)}$

$g=3.8m{s}^{-2}$

Hence, the value of g on mars is $3.8m{s}^{-2}$.