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Question

Calculate the amount and compound interest on

(a) Rs.10,800 for 3 years at 1212% per annum compounded annually.

(b) Rs.18,000 for 212 years at 10% per annum compounded annually.

(c) Rs.62,500 for 112 years at 8% per annum compounded half yearly.
(d) Rs.8,000 for 1 year at 9% per annum compounded half yearly.
(e) Rs.10,000 for 1 year at 8% per annum compounded half yearly.

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Solution

a) Given:

Prinicipal (P) = Rs.10800, Rate(R)= 1212%=252% paTime (n) = 3 years
Since, A=P(1+r100)n =10800(1+12.5100)3
=10800(1.423)
=15377.34
Thus, A=Rs.15377.34

CI=AP=1537710800=Rs.4577.34

b) Given:

Principal(P) = Rs.18000

Rate (r) = 10%

Time(n) = 212years

Now, when time is in fraction, we use CI formula for the whole number of the mixed fraction and on the fraction part we use the formula of simple interest.

Thus, compound interest for 2 years
A=P(1+r100)n=18000(1+10100)2=18000(1.21)=21780

Now, this will act as Prinipal for SI

SI=P×R×T100=217800×10×1200=10890

A=21780+10890=Rs.32670 and
Therefore, CI=AP
=3267018000
=Rs.14670


c) Given:

Prinicpal(P)=Rs.62500

Rate(r)=8% pa 8%2=4%compounded half yearly

Time(n) = 112 years compounded yearly.

n=32×2=3 compounded half yearly

A=P(1+r200)n=62500(1+4200)3=62500(1+150)3=62500×5150×5150×5150=66325.5
A=Rs.66325.5

CI=AP=Rs.66325.562500=Rs.3825.5

d) Given:

Prinipal (P) = Rs.8000

Time(n) = 1 year compounded annually.

n=1×2=2 compounded half yearly

Rate(r)=9%2 compounded half yearly

A=P(1+r200)n=8000(1+9200)2=8000(1.092)=8736.2
A=Rs.8736.20
CI=AP=Rs.736.20

e) Given:

Principal(P)=Rs.10000

Time(n)=1 year compounded annually

n=1×2=2 compounded half yearly

Rate(r) =8%2 compounded half yearly

A=P(1+r200)n=10000(1+8200)2=10000(1.0816)=10816

A=Rs.10816
Therefore, CI=AP=Rs.816

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