Calculate the amount and compound interest on
$R s . 18, 000$ for $2 \frac{1}{2}$ year at $10$ % per annum compounded annually.

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Solution

P = 18000 ; R = 10%, T=2.5.
So Let T = 2
$A = 18000 (1 + \frac{10}{100})^{2}$
$18000 (11 / 10)^{2}$
$= 21780.$
Interest after 2 years
$= 21780 - 18000 = 3780$
Interest after half year
$= 21780 \times \frac{10}{100} \times \frac{1}{2} = 1089$
Total interest after 2.5 year
$3780 + 1089 = 4869.$

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Rs

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2 \frac{1}{2}

years at

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Calculate the amount and compound interest on
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Calculate the amount and compound interest on:
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Compound interest on ₹ 18,000 for $2 \frac{1}{2}$ years at 10% per annum, compounded annually is

Question 1 (b)
Calculate the amount and compound interest on:

b) ₹18,000 for $2 \frac{1}{2} %$ years at 10% per annum compounded annually.

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Calculate the amount and compound interest onRs. 18,000 for 212 year at 10% per annum compounded annually.

P = 18000 ; R = 10%, T=2.5.So Let T = 2 A=18000(1+10100)218000(11/10)2=21780.Interest after 2 years=21780−18000=3780Interest after half year=21780×10100×12=1089Total interest after 2.5 year3780+1089=4869.

Calculate the amount and compound interest on
$R s . 18, 000$ for $2 \frac{1}{2}$ year at $10$ % per annum compounded annually.

P = 18000 ; R = 10%, T=2.5.
So Let T = 2
$A = 18000 (1 + \frac{10}{100})^{2}$
$18000 (11 / 10)^{2}$
$= 21780.$
Interest after 2 years
$= 21780 - 18000 = 3780$
Interest after half year
$= 21780 \times \frac{10}{100} \times \frac{1}{2} = 1089$
Total interest after 2.5 year
$3780 + 1089 = 4869.$