Question

Calculate the amount of $CaC{O}_3$ (m wt = 100 gm/mole) is need to produce 336 kg of $CaO$ (m. wt = 56 gm/ mole), according to reaction:

$CaC{O}_3\left(s\right)\to CaO\left(s\right)+C{O}_2\left(g\right)$.

The $\%$ yield of the reaction is $60\%$.

• A. ${10}^3$
• B. ${10}^2$
• C. $900$
• D. $800$

Answer 1

Answer: (A)

${10}^3$

$\underset{100g}{CaC{O}_3}\to \underset{56g}{CaO+}C{O}_2$

For $100\%$ yield$\to 56gCaO$ formed

For $60\%$ yield$\to xgCaO$ formed

$65\times 56=x\times 100$

$x=33.6g$

$100g$ gives $33.6g$

$x$ gives $336g$

$100\times 336\times {10}^3=33.6\times x$

$x={10}^{6}g$

$x={10}^{3}kg$