Calculate the amount of carbon dioxide evolved if 440 grams of propane $(C_{3} H_{8}$ ) is combusted with oxygen. Also, calculate the number of moles of oxygen required to combust 10 moles of propane.

Open in App

Solution

Given that
$(i)$ Mass of propane $(w) = 440 g .$

Now,
$(i) C_{3} H_{8} + 50_{2} \to 3 C O_{2} + 4 H_{2} O$

$44 g - - - - - 3 \times 44 g C O_{2}$
$∴ 440 g p r o d u c e s - - - ? (x)$

Now, $\frac{x}{3 \times 44} = \frac{440}{44}$

$x = \frac{440 \times 3 \times 44}{44}$

$= 1320 g$

$∴$ Mass of $C O_{2}$ evolved $(w) = 1320 g$

$(i i) C_{3} H_{8} + S O_{2} \to 3 C O_{2} + 4 H_{2} O$
$1 m o l 5 m o l 3 m o l$

$10 m o l e s - - - - 5 \times 10 m o l e s$

$= 50 m o l e s$

$∴$ Moles of $O_{2}$ required $(x) = 50 m o l e s$

Suggest Corrections

Similar questions

C_{3} H_{8}

2 M g + O_{2} \to 2 M g O

10

O_{2}

(C_{3} H_{8})

What volume of oxygen at STP is required to affect the combustion of 10 litres of propane $(C_{3} H_{8})$ at 540 K and 250 mm of Hg pressure?

Join BYJU'S Learning Program