Calculate the amount of charge flowing in 2 min in a wire of resistance 10- when a potential difference of 20V is applied between its ends-

The correct option is B 240C t = 2 min = 120 second. R= 10Ω , V = 20 volt ⇒ current i=VR=2010= 2 Ans ⇒ charge 2=it=2× 120=240 co ...

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Standard X

Physics

Electric Potential and Potential Difference

Calculate the...

Question

Calculate the amount of charge flowing in $2$ min in a wire of resistance $10 Ω$ when a potential difference of $20 V$ is applied between its ends.

120 C

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240 C

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20 C

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4 C

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Solution

The correct option is B $240 C$
t = 2 min = 120 second.
$R = 10 Ω$ , V = 20 volt
$\Rightarrow$ current $i = \frac{V}{R} = \frac{20}{10} = 2$ Ans
$\Rightarrow$ charge $2 = i t = 2 \times 120 = 240$ coulomb

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Calculate the amount of charge flowing in 2 min in a wire of resistance 10Ω when a potential difference of 20V is applied between its ends.

The correct option is B 240Ct = 2 min = 120 second.R=10Ω, V = 20 volt⇒ current i=VR=2010=2 Ans⇒ charge 2=it=2×120=240 coulomb

Calculate the amount of charge flowing in $2$ min in a wire of resistance $10 Ω$ when a potential difference of $20 V$ is applied between its ends.

The correct option is B $240 C$
t = 2 min = 120 second.
$R = 10 Ω$ , V = 20 volt
$\Rightarrow$ current $i = \frac{V}{R} = \frac{20}{10} = 2$ Ans
$\Rightarrow$ charge $2 = i t = 2 \times 120 = 240$ coulomb