Calculate the amount of charge that would flow in $2 h o u r s$ through an element of an electric bulb carrying a current of $0.25 A$

Ammeter

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Voltmeter

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manometer

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water meter

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Solution

The correct option is
A

Ammeter

Given.

time $t$ = $2 h r s$ = $7200 s$

Current, $I$ = $0.25 A$

$I = \frac{Q}{t}$

Therefore, $Q$ = $I \times t$ = $7200 \times 0.25$

= $1800 C$

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