The correct option is A 804.3 g
To prevent the water from freezing at −6∘C, the frezzing point of water should drop to −6∘C.
Thus, the depression in freezing point △Tf=6∘C
We know,
Freezing point depression of a solution is given by,
△Tf=Kf×m
where,
△Tf is the depression in freezing point.
Kf is molal depression constant.
m is molality of solution.
Given:
ΔT=6∘CWeight of solvent, W=4 kg=4000 gMolar mass of solute, M=62 g/molKf of water =1.85 K kg mol−1Molality=△TfKfw=M×W×ΔT1000×Kf
where, w is the weight of the solute
∴w=62×4000×61000×1.85=804.3 g
Thus, the amount of ethylene glycol to be added to 4 kg of water to prevent it from freezing at −6∘C is 804.3 g