Question

Calculate the amount of force P which will just lift the total weight of 200 N acting on the wheelbarrow as shown in figure.

• A. 90.91 N
• B. 89.56 N
• C. 91.90 N
• D. 87.89 N

Answer 1

The correct option is A

90.91 N

Given: length of the load arm = 50 cm, length of the effort arm = (60 + 50) cm and load = 200 N
In equilibrium,
Effort $\times$ Effort arm = Load $\times$ Load arm
$\Rightarrow$ P $\times$ 110 = 200 $\times$ 50
$\Rightarrow$ $P=\frac{200\times 50}{110}=90.91N$