Calculate the amount of heat energy required to convert 1 kg of ice into water at melting point.

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Solution

$Latent heat of fusion = 336 J/g$
$Mass of ice = 10 kg$
$1 kg = 1000 g$
$∴ Mass of ice in grams = 10 \times 1000 g = 10000 g$
$Total heat required = mass of ice \times latent heat of fusion$
$= 10000 g \times 336 J/g$
$= 3360000 J$
$∴ 3360000 J of heat energy is required to convert 1 kg of ice into water at its meltinging point.$

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