Calculate the amount of heat energy required to raise the temperature of $1$ kg of iron from $20^{\circ} C t o 100^{\circ} C$ . $c = 483 J {k g}^{- 1} K^{- 1}$ .

35674 J

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48266 J

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38640 J

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56446 J

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Solution

The correct option is D 38640 J
Given:
mass $(m) = 1 k g$
Heat energy required $(Q) = ?$
Rise in temperature $Δ t = 100 - 20 = 80^{\circ} C = 80 K$
Specific heat capacity $(c)$ $483 J {k g}^{- 1} K^{- 1}$
Specific heat capacity $(c)$ $= \frac{H e a t e n e r g y (Q)}{M a s s (m) \times R i s e i n t e m p e r a t u r e}$
$483 = Q / (1 \times 80)$
$Q = 38640 J$

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