Question

Calculate the amount of heat generated while transferring 90,000 coulombs of charge between the two terminals of a battery of 40 v in one hour.

Answer 1

$Q=90000C,t=1hr=3600s,V=40V$

$I=\frac{Q}{t}=\frac{90000}{3600}=25A$

$R=\frac{v}{I}=\frac{40}{25}=1.6\Omega$

$H=I^{2}Rt=25\times 25\times 1.6\times 3600$

$H=36\times {10}^{5}J=3600kJ$