Calculate the amount of heat (in calories) required to convert 5 gram of ice at zero degree celsius, to steam at hundred degree Celsius.

3100

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3200

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3600

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4200

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Solution

The correct option is C $3600$
Lets do step by step,

5g ice at zero to 5g water at zero,

$Q_{1} = m \times l_{f} = 5 \times 80 = 400 c a l$

5g water at 0 to 5g water at 100°C,

$Q_{2} = m s Δ T = 5 \times 1 \times 100 = 500 c a l$

5g water at 100°C to 5g steam at 100°C,

$Q_{3} = m l_{v} = 5 \times 540 = 2700 c a l$

$Q = Q_{1} + Q_{2} + Q_{3} = 3600 c a l$

Option $C$ is the correct answer

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Calculate the amount of heat (in calories) required to convert 5 gram of ice at zero degree celsius, to steam at hundred degree Celsius.

The correct option is C 3600Lets do step by step,5g ice at zero to 5g water at zero,Q1=m×lf=5×80=400 cal5g water at 0 to 5g water at 100°C,Q2=msΔT=5×1×100=500 cal5g water at 100°C to 5g steam at 100°C,Q3=mlv=5×540=2700 calQ=Q1+Q2+Q3=3600 calOption C is the correct answer