Calculate the amount of heat required to convert 1.00 kg of ice at −10∘C into steam at 100∘C at normal pressure. (Sice=2100 J kg−1K−1, Swater=4200 J kg−1K−1, Lf,ice=3.36×105 J kg−1, Lv,water=2.25×106 J kg−1)
Calculate the amount of heat required to convert 1.00 kg of ice at -10°C at normal pressure to steam at 100°C.
The specific heat capacity of ice=2100 Jkg−1K−1
Latent heat of fusion of ice=3.36×105 Jkg−1
The specific heat capacity of water=4200 Jkg−1K−1
Latent heat of vaporization of water=2.25×106 Jkg−1
The amount of heat energy required to convert 1 kg of ice at −10∘C to water at 100∘C is 7,77,000 J. Calculate the specific latent heat of ice.
Specific heat capacity of ice = 2100 J kg−1 K−1, specific heat capacity of water=4200 J kg−1 K−1.
1 kg of ice at 0∘C is mixed with 1 kg of steam at 100∘C. What will be the composition of the system when thermal equilibrium is reached? Latent heat of fusion of ice = 3.36 × 105 J kg−1, specific heat capacity of water = 4200 J kg −1 K−1 and latent heat of vaporization of water = 2.26 × 106 J kg−1