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Question

Calculate the amount of heat required to convert 1.00 kg of ice at 10C into steam at 100C at normal pressure. (Sice=2100 J kg1K1,
Swater=4200 J kg1K1,
Lf,ice=3.36×105 J kg1,
Lv,water=2.25×106 J kg1)

A

3.03×106 J

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B

4.03×106 J

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C

5.03×106 J

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D

6.03×106 J

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Solution

The correct option is B

3.03×106 J


Heat required to heat ice from 10C to ice at 0C is:
Q1=mSiceΔT1
Q1=1 kg×2100 J kg1K1×10 K
Q1=21000 J

Heat required to covert ice to water is:
Q2=mLf,ice
Q2=1 kg×3.36×105 J kg1
Q2=336000 J

Heat required to heat water from 0C to water at 100C is:
Q3=mSwaterΔT3
Q3=1 kg×4200 J kg1k1×100
Q3=420000 J

Heat required to covert water to steam is:
Q4=mLv,water
Q4=1 kg×2.25×106 J kg1
Q4=2250000 J

Total heat required is:
Q=Q1+Q2+Q3+Q4
Q=(21+336+420+2250) kJ
Q=3.027×106 J

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