Calculate the amount of heat required to vapourise 2 kg of water at 100- C- for which the latent heat of vapourisation is 2260 kJ - kg-A- 2260 kJB- 9460 kJC- 9420 kJD- 4520 kJ

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Question

Calculate the amount of heat required to vapourise $2 k g$ of water at $100^{\circ} C$ , for which the latent heat of vapourisation is $2260 k J / k g$ .

2260 k J

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9460 k J

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9420 k J

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4520 k J

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Solution

The correct option is D $4520 k J$
Given:
Mass of water, $m = 2 k g$
Latent heat of vapourisation, $L = 2260 k J / k g$
Heat required to vapourise water is:
$Q = m L$
$Q = 2 \times 2260$
$Q = 4520 k J$ .

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Calculate the amount of heat required to vapourise 2 kg of water at 100∘C, for which the latent heat of vapourisation is 2260 kJ/kg.

The correct option is D 4520 kJGiven: Mass of water, m=2 kg Latent heat of vapourisation, L=2260 kJ/kg Heat required to vapourise water is: Q=mL Q=2×2260 Q=4520 kJ.

Calculate the amount of heat required to vapourise $2 k g$ of water at $100^{\circ} C$ , for which the latent heat of vapourisation is $2260 k J / k g$ .

The correct option is D $4520 k J$
Given:
Mass of water, $m = 2 k g$
Latent heat of vapourisation, $L = 2260 k J / k g$
Heat required to vapourise water is:
$Q = m L$
$Q = 2 \times 2260$
$Q = 4520 k J$ .