Question

Calculate the amount of lime that can be produced by heating 100 g of 90% pure limestone:

• A. 50.4 g
• B. 0.98 mol
• C. 0.9 mol
• D. 56 g

Answer 1

The correct option is A 50.4 g

$CaC{O}_3\to CaO+C{O}_2$

Molecular weight: $CaC{O}_3$ = 100g and $CaO$ = 56g

100 g of $CaC{O}_3$ gives 56g of $CaO$

Pure $CaC{O}_3=\frac{90}{100}\times 100=90g$

So, $90g$ of $CaC{O}_3$ will gives $=\frac{56}{100}\times =50.4g$ of $CaO$.

Hence option A is correct.