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Question

Calculate the amount of lime that can be produced by heating 100 g of 90% pure limestone:

A
50.4 g
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B
0.98 mol
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C
0.9 mol
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D
56 g
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Solution

The correct option is A 50.4 g
CaCO3CaO+CO2

Molecular weight: CaCO3 = 100g and CaO = 56g

100 g of CaCO3 gives 56g of CaO

Pure CaCO3=90100×100=90g

So, 90g of CaCO3 will gives =56100×=50.4g of CaO.

Hence option A is correct.

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