Calculate the amount of polythene formed from 20 kg of Calcium Carbide from the reaction given below Ca OH 2- C 2 H 2CaC 2-2 H 2 O pd - BaSO 4- Ca OH 2-Hc - CH - H 2 pd H 2 C - CH 2n- CH 2- CH 2t T CH 2- CH 2-A- 28 gB- 64 kgC- 9 gD- 8 kg

The correct option is D 8kg ...

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Faraday's First Law

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Calculate the amount of polythene formed from 20kg of Calcium Carbide from the reaction given below

28g

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8kg

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64kg

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C a C_{2} + 2 H_{2} O \to C a (O H)_{2} + C_{2} H_{2}

H C \equiv C H + H_{2} P d - B a S O_{4} \to C H_{2} = C H_{2}

n C H_{2} = C H_{2} \to (C H_{2} - C H_{2})_{n}

20

C a C_{2} + 2 H_{2} O \to C a (O H)_{2} + C_{2} H_{2}

H C \equiv C H + H_{2} P d \cdot B a S O_{4} - ----- \to C H_{2} = C H_{2}

n C H_{2} = C H_{2} \to (- C H_{2} - C H_{2} -)_{n} P o l y t h e n e

C a C_{2} + 2 H_{2} O ⟶ C a {(O H)}_{2} + C_{2} H_{2} H C

C H \equiv C H + H_{2} p d . B a S O_{4} ⟶ C H_{2} = C H_{2}

n C H_{2} = C H_{2} ⟶ {(- C H_{2} - C H_{2} -)}_{n} P o l y t h e n e

C a C_{2} + 2 H_{2} O \to C a (O H)_{2} + C_{2} H_{2}

C_{2} H_{2} + H_{2} \to C_{2} H_{4}

n C_{2} H_{4} \to (C H_{2} - C H_{2}) n

C a C_{2}

C a C_{2} + 2 H_{2} O \to C a (O H)_{2} + C_{2} H_{2}

C_{2} H_{2} + H_{2} \to C_{2} H_{4}

n C_{2} H_{4} \to (C H_{2} - C H_{2})_{n}

64

C a C_{2}

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