CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Calculate the amount of precipitate of BaSO4 formed when 30 mL of 0.1 M BaCl2 is mixed with 40 mL of 0.2 M Al2(SO4)3.
(Molar mass of barium = 137 g/mol, Molar mass of Al = 27 g/mol).

A
0.7 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.5 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.2 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.8 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.7 g
Balanced chemical reaction:
moles before Reaction3BaCl23×103+Al2(SO4)38×1033BaSO40+2AlCl30
moles after Reaction3BaCl20+Al2(SO4)37×1033BaSO43×103+2AlCl32×103

Number of moles of BaSO4 formed=3×103 mol
Mass of precipitate formed=mole×molar mass=3×103×233=0.699 g0.7g

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon