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Depression in Freezing Point

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Question

Calculate the amount of sodium chloride which must be added to one kilogram of water so that the freezing point of water is depressed by 3 K. (Given, $K_{f}$ =1.86 K kg $m o l^{- 1}$ , atomic mass of Na=23, Cl=35.5).

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Solution

$Δ T_{f} = k_{f} \times m o l a r i t y$
$\Rightarrow 3 = 1.86 \times \frac{\frac{w}{58.5}}{1}$
$\Rightarrow w = \frac{3 \times 58.5}{1.86}$
$= 94.35 g m$

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