Question

Calculate the amount of water (g) product by the combustion of $16g$ of methane.

Answer 1

Combustion of methane :

$C{H}_4+2O_2⟶C{O}_2+2H_{2}O$

Given weight of methane $=16g$

Molecular weight of methane $=16g$

No. of moles of methane in 16g of it $=\frac{\text{given wt.}}{\text{mol. wt.}}=\frac{16}{16}=1\text{mole}$

From the reaction,

Amount of water produced by the combustion of 1 mole of methane = 2 moles

weight of 1 mole of water $=18g$

$\Rightarrow$ weight of 2 moles of water $=2\times 18=36g$

Since, the given weight of methane is 16 g, hence the water produced by the combustion of 16 g of methane is 36 g.