Calculate the amount of work done required in moving 28-1020 electrons across two points of a wire with a potential difference of 14 V-

Given: Potential difference, V = 18 V No. of electrons, n = 28 × 10^20 nbsp; Magnitude of charge on an electron, e = 1.6 × 10^ 19 C So total charge that has ...

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Standard X

Physics

Electric Current(I)

Calculate the...

Question

Calculate the amount of work done required in moving $28 \times 10^{20}$ electrons across two points of a wire with a potential difference of $14 V$ .

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Solution

Given:
Potential difference, $V = 18 V$
No. of electrons, $n = 28 \times 10^{20}$
Magnitude of charge on an electron, $e = 1.6 \times 10^{- 19} C$

So total charge that has to be moved is:
$Q = n e$
$Q = 28 \times 10^{20} \times 1.6 \times 10^{- 19} C$
$Q = 448 C$

Work done in moving this amount of charge,
$W = V Q$
$W = 14 V \times 448 C$
$W = 6272 J$

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Calculate the amount of work done required in moving 28×1020 electrons across two points of a wire with a potential difference of 14 V.

Given: Potential difference, V=18 V No. of electrons, n=28×1020 Magnitude of charge on an electron, e=1.6×10−19 C So total charge that has to be moved is: Q=ne Q=28×1020×1.6×10−19 C Q=448 C Work done in moving this amount of charge, W=VQ W=14 V×448 C W=6272 J

Calculate the amount of work done required in moving $28 \times 10^{20}$ electrons across two points of a wire with a potential difference of $14 V$ .