Calculate the angle of $1^{'}$ (minute of arc or arcmin)

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Solution

The angle can be written as,
$1^{'} = {(1 / 60)}^{\circ}$
$1^{'} = \frac{2 π}{360 \times 60} r a d$
$1^{'} = 0.00029 r a d$

Thus, the angle of $1^{'}$ is equal to $0.00029 r a d$ .

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Similar questions

Calculate the angle of $(a) 1^{\circ} (degree) (b) 1'$ (minute of arc or arcmin) and $(c) 1^{''}$ (second of arc or arc second) in radians. Use $360^{\circ} = 2 π rad, 1^{\circ} = 60^{'} and 1' = 60$

Calculate the angle of (a) $1^{\circ}$ (degree) (b) $1^{'}$ (minute of arc or arc min) and (c) $1^{''}$ (second of arc or arc second) in radians.
Use $360^{\circ} = 2 π$ radian, $1^{\circ} = 60^{'}$ and $1^{'} = 60^{''}$

Q. Calculate the angle 1''(second of arc or arc of second) in radians.
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(second of arc or arc second) in radians.
Use

360^{o} = 2 π

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1^{o} = 60^{'}

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1^{'} = 60^{'}

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Calculate the angle of 1′ (minute of arc or arcmin)

The angle can be written as,1′=(1/60)∘1′=2π360×60rad1′=0.00029rad Thus, the angle of 1′ is equal to 0.00029rad.

Calculate the angle of $1^{'}$ (minute of arc or arcmin)

The angle can be written as,
$1^{'} = {(1 / 60)}^{\circ}$
$1^{'} = \frac{2 π}{360 \times 60} r a d$
$1^{'} = 0.00029 r a d$

Thus, the angle of $1^{'}$ is equal to $0.00029 r a d$ .