Calculate the angle of $1 "$ (second of arc or arc second) in radians.
Use $360^{o} = 2 π$ rad $1^{o} = 60^{'}$ and $1^{'} = 60^{'}$

Open in App

Solution

The angle can be written as,

$1^{''} = {(1 / 3600)}^{\circ}$

$1^{''} = \frac{2 π}{360 \times 3600} r a d$

$1^{''} = 0.0000048 r a d$

Thus, the angle of $1^{''}$ is equal to $0.0000048 r a d$ .

Suggest Corrections

Similar questions

Calculate the angle of (a) $1^{\circ}$ (degree) (b) $1^{'}$ (minute of arc or arc min) and (c) $1^{''}$ (second of arc or arc second) in radians.
Use $360^{\circ} = 2 π$ radian, $1^{\circ} = 60^{'}$ and $1^{'} = 60^{''}$

Calculate the angle of $(a) 1^{\circ} (degree) (b) 1'$ (minute of arc or arcmin) and $(c) 1^{''}$ (second of arc or arc second) in radians. Use $360^{\circ} = 2 π rad, 1^{\circ} = 60^{'} and 1' = 60$

Q. Calculate the angle 1''(second of arc or arc of second) in radians.
please explain it a little elaborately

Q. Calculate the angle of

1^{'}

(minute of arc or arcmin)

For constructing an angle of $60^{\circ}$ , we need to draw __ arc/arcs.

Join BYJU'S Learning Program

Calculate the angle of 1" (second of arc or arc second) in radians.Use 360o=2π rad 1o=60′ and 1′=60′

The angle can be written as, 1′′=(1/3600)∘ 1′′=2π360×3600rad 1′′=0.0000048rad Thus, the angle of 1′′ is equal to 0.0000048rad.

Calculate the angle of $1 "$ (second of arc or arc second) in radians.
Use $360^{o} = 2 π$ rad $1^{o} = 60^{'}$ and $1^{'} = 60^{'}$

The angle can be written as,

$1^{''} = {(1 / 3600)}^{\circ}$

$1^{''} = \frac{2 π}{360 \times 3600} r a d$

$1^{''} = 0.0000048 r a d$

Thus, the angle of $1^{''}$ is equal to $0.0000048 r a d$ .