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Question

Calculate the angular orbital momentum of the orbiting electron in the fifth orbit of an atom.

A
5.25×1034 kg m2s1
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B
5.25×1043 kg m2s1
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C
5.25×1034 kg m2s1
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D
6.25×1034 kg m2s1
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Solution

The correct option is C 5.25×1034 kg m2s1
According to Bohr's second postulate, the angular orbital momentum of a revolving electron is given by,

L=nh2π

So, for n=5, we have,

L=5×6.6×10342π=5.25×1034 kgm2s1

Hence, option (C) is the correct answer.

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