A boy of mass 40 kg is standing in a lift,
which is moving downwards with an acceleration 9.8 $m / s^{2}$ . The apparent weight of
the boy is (Take $g = 9.8 m / s^{2}$ )

Q. What is the weight of a block of mass 250g? [ Take

g = 10 m / s^{2}]

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Calculate the apparent weight of a stone whose weight in the air is 250 g and the upthrust is 0.8 N.(take g = 9.8 ms−2)

The correct option is B 1.65 N Given: m = 250 g = 0.25 kg, U = 0.8 N, g = 9.8 m/s² Using, W = mg = 0.25 × 9.8 = 2.45 N We know that, Apparent weight = Actual weight - Upthrust i.e. Apparent weight = 2.45 - 0.8 = 1.65 N (Answer)

Calculate the apparent weight of a stone whose weight in the air is 250 g and the upthrust is 0.8 N. $(t a k e g = 9.8 m s^{-} 2)$

The correct option is B
1.65 N

Given: m = 250 g = 0.25 kg, U = 0.8 N, g = 9.8 m/s²

Using, W = mg = 0.25 $\times$ 9.8 = 2.45 N

We know that, Apparent weight = Actual weight - Upthrust

i.e. Apparent weight = 2.45 - 0.8 = 1.65 N (Answer)