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Standard XII

Chemistry

Heat of Reaction

Calculate the...

Question

Calculate the approximate energy released from the following experiment -
500 mL of 1.0 M HCl with 500 mL of 1.0 M NaOH is neutralizing and the temperature of the solution rises ${5.0}^{\circ} C$ .
Density of the solution is 1.0 g/mL and specific heat of the solution is 4.184 J/g $^{\circ}$ C.

20 J

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1000 J

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4200 J

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2.1 \times 10^{4}

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1.0 \times 10^{4}

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Solution

The correct option is D $2.1 \times 10^{4}$ J
Total volume of solution $= 500 + 500 = 1000$ mL.
The density of the solution is 1 g/mL
Total mass of solution $=$ Density $\times$ volume $= 1.0$ g/mL $\times 1000$ mL $= 1000$ g.
Approximate energy released $q =$ mass $\times$ specific heat of the solution $\times$ temperature change
$q = 1000 \times 4.184 \times 5.0 = 2.1 \times 10^{4}$ J

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Calculate the approximate energy released from the following experiment -500 mL of 1.0 M HCl with 500 mL of 1.0 M NaOH is neutralizing and the temperature of the solution rises 5.0∘C.Density of the solution is 1.0 g/mL and specific heat of the solution is 4.184 J/g ∘C.

Calculate the approximate energy released from the following experiment -
500 mL of 1.0 M HCl with 500 mL of 1.0 M NaOH is neutralizing and the temperature of the solution rises ${5.0}^{\circ} C$ .
Density of the solution is 1.0 g/mL and specific heat of the solution is 4.184 J/g $^{\circ}$ C.