Calculate the aqueous solubility of $C a (O H)_{2}$ in grams per litre. $[K_{s p} = 8.0 \times 10^{- 6}]$

5.9 \times 10^{- 4}

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2.0 \times 10^{- 2}

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0.93

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1.5

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Solution

The correct option is C $0.93$
$C a C O H_{2} ⇋ [C a^{2 +}] + 2 [O H^{-}]$
$⟹ 4 S^{2} = K s p$
$S = \sqrt{\frac{8 \times 10^{- 6}}{4}} = \frac{1.2599}{100} \frac{m o l}{l i t e r}$
$1$ mole $= 74 g ⟹ S = \frac{1.2599}{100} \frac{m o l}{l i t e r} \times 74 \frac{g}{m o l}$
$⟹ S = 0.93 \frac{g}{l i t e r}$

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