Question

Calculate the area enclosed by a rectangular shape, whose breadth is $10cm$ and the length is twice its breadth.

• A. $100c{m}^2$
• B. $200c{m}^2$
• C. $400c{m}^2$
• D. $50c{m}^2$

Answer 1

The correct option is B $200c{m}^2$

Given:
Breadth of the rectangle, $b=10cm$
Length of the rectangle is twice the breadth $\Rightarrow l=2\times b$
$\Rightarrow l=2\times 10cm$
$\Rightarrow l=20cm$
Now area of the rectangle, $A=l\times b$
Hence, $A=20cm\times 10cm$
$\Rightarrow A=200c{m}^2$
Therefore, the area of the rectangle is $200c{m}^2$.