Calculate the area enclosed under the curve $f (x) = x^{2}$ between the limits $x = 2$ and $x = 3$ .

Open in App

Solution

$\int_{2}^{3} f (x) d x = \int_{2}^{3} x^{2} d x$
$= \frac{x^{3}}{3} |_{2}^{3}$
$= \frac{(3)^{3}}{3} - \frac{(2)^{3}}{3} = \frac{19}{3} = 6.333$ .

Suggest Corrections

Similar questions

x^{2} = y

y^{2} = x

y^{2} = x a n d y = | x |

f (x) = x^{\frac{2}{3}}, x \geq 0

y = f (x)

y = x, x = 1

x = 8

x^{2} + y^{2} = 4

x = \frac{y}{\sqrt{3}}

Find the area enclosed between the curve $y = 5 x - x^{2} a n d y = x$ .

Join BYJU'S Learning Program