Question

Calculate the area of a rhombus having diagonals equal to 6 cm and 8 cm respectively.

Answer 1

Given that,

Diagonal 1, $d_1=6$ cm

Diagonal 2, $d_2=8$ cm

Area of a rhombus, $A=\frac{d_1\times d_2}{2}$

$=\frac{6\times 8}{2}$

$=\frac{48}{2}$

$=24c{m}^2$

Hence, the area of the rhombus is 24 cm${}^2.$