Question

Calculate the area of a trapezium whose parallel sides are $14$ cm and $5$ cm, and the height is $20$ cm.

• A. $180$ $c{m}^2$
• B. $190$ $c{m}^2$
• C. $290$ $c{m}^2$
• D. $170$ $c{m}^2$

Answer 1

The correct option is B $190$ $c{m}^2$

Area of a trapezium = $\frac{1}{2}(b_1+b_2)\times h$
Given: $b_1=$ $14$ cm
$b_2=$ $5$ cm
$h=20$ cm
$A=\frac{1}{2}(14+5)\times 20$
$A=\frac{1}{2}\times 19\times 20$
$A=190$ $c{m}^2$