Question

Calculate the area of the trapezium shown in the figure:

Answer 1

$C{O}^2=C{B}^2-O{B}^2$

$⟹C{O}^2={17}^2-8^2$

$⟹CO=15\text{cm}$

Area of trapezium $=\frac{1}{2}\times$ altitude $\times$ sum of parallel sides

$\therefore$ Area $=\frac{CO}{2}(DC+AB)$

Area $=\frac{15}{2}(6+6+8)$

Area $=150{\text{cm}}^2$