Question

Calculate the area of triangle formed by joining the points (4,0),(0,0) and (0,4)

Answer 1

Dear student
$$\begin{gathered} LetA=\left(x_1,y_1\right)=\left(4,0\right),B=\left(x_2,y_2\right)=\left(0,0\right),C=\left(x_3,y_3\right)=\left(0,4\right) \\ bethegivenpoints.Then, \\ Areaof△ABC=\frac{1}{2}\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right| \\ =\frac{1}{2}\left|4\left(0-4\right)+0(4-0)+0(0-0)\right| \\ =\frac{1}{2}\left|-16\right| \\ =8sq.units \end{gathered}$$
Regards