Question

Calculate the average kinetic energy per mole of $C{O}_2$ gas at ${27}^{\circ }C$ in different units.

Answer 1

$KE=\frac{3}{2}nRT$
$=\frac{3}{2}\times 1\times 1.987\times 300=894.15cal$
$KE=\frac{3}{2}nRT$
$=\frac{3}{2}\times 1\times 8.314\times 300$
$=3741J$
$=3.741\times {10}^{10}erg$