Question

Calculate the average molecular kinetic energy:
Per kilogram
($R=8320J/KmolK$, Avogadro's number $=6.03\times {10}^{26}m$ molecules /$Kmole$)

Answer 1

$E=nRT$

$=6.03\times {10}^{26}\times 8320\times {10}^3$

$=5.61\times {10}^{30}J/K\times {10}^3$

$=5.61\times {10}^{33}J/K$.