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Byju's Answer
Standard XII
Chemistry
Rate of Reaction
Calculate the...
Question
Calculate the average rate of decomposition of
N
2
O
5
by the reaction,
2
N
2
O
5
(
g
)
⟶
4
N
O
2
(
g
)
+
O
2
(
g
)
.
During the time interval from
t
=
600
s
to
t
=
1200
s
using the following data:
T
i
m
e
[
N
2
O
5
]
600
s
1.24
×
10
−
2
M
1200
s
0.93
×
10
−
2
M
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Solution
Average rate of decomposition of
N
2
O
5
=
−
1
△
[
N
2
O
5
]
2
△
t
=
−
1
2
[
0.93
×
10
−
2
−
1.24
×
10
−
2
]
M
1200
−
600
s
=
−
(
−
0.31
)
600
×
10
−
2
M
s
−
1
=
0.051
2
×
10
−
4
M
s
−
1
=
0.026
×
10
−
4
M
s
−
1
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0
Similar questions
Q.
The decomposition of
N
2
O
5
according to the equation,
2
N
2
O
5
(
g
)
⟶
4
N
O
2
(
g
)
+
O
2
(
g
)
, is a first order reaction. After
30
minutes from the start of the decomposition in a closed vessel, the total pressure developed is found to be
284.5
m
m
H
g
and on completion, the total pressure is
584.5
m
m
H
g
. Calculate the rate constant of the reaction.
Q.
Calculate
Δ
H
/
k
J
for the following reaction using the listed standard enthalpy of reaction data:
2
N
2
(
g
)
+
5
O
2
(
g
)
⟶
2
N
2
O
5
(
s
)
N
2
(
g
)
+
3
O
2
(
g
)
+
H
2
(
g
)
⟶
2
H
N
O
3
(
a
q
)
Δ
H
/
k
J
=
−
414.0
N
2
O
5
(
s
)
+
H
2
O
(
I
)
⟶
2
H
N
O
3
(
a
q
)
Δ
H
/
k
J
=
−
86.0
2
H
2
(
g
)
+
O
2
(
g
)
⟶
2
H
2
O
(
I
)
Δ
H
/
k
J
=
−
571.6
Q.
For a first order reaction involving decomposition of
N
2
O
5
, the following information is available :
2
N
2
O
5
(
g
)
→
4
N
O
2
(
g
)
+
O
2
(
g
)
Rate = k
[
N
2
O
5
]
N
2
O
5
(g)
→
2
N
O
2
(g) +
1
2
O
2
(g) Rate =
k
′
[
N
2
O
5
]
,
Which of the following expressions is true ?
Q.
The rate constant for the reaction,
N
2
O
5
(
g
)
⟶
2
N
O
2
(
g
)
+
1
2
O
2
(
g
)
, is
2.3
×
10
−
2
s
e
c
−
1
. Which equation given below describes the change of
[
N
2
O
5
]
with time,
[
N
2
O
5
]
0
and
[
N
2
O
5
]
t
corresponds to concentration of
N
2
O
5
initially and time
t
respectively?
Q.
Calculate
Δ
H
/
k
J
for the following reaction using the listed standard enthalpy of reaction data.
2
N
2
(
g
)
+
5
O
2
(
g
)
⟶
2
N
2
O
5
(
s
)
N
2
(
g
)
+
3
O
2
(
g
)
+
H
2
(
g
)
⟶
2
H
N
O
3
(
a
q
)
;
Δ
H
/
k
J
=
−
414.0
N
2
O
5
(
s
)
+
H
2
O
(
l
)
⟶
2
H
N
O
3
(
a
q
)
;
Δ
H
/
k
J
=
−
86.0
2
H
2
(
g
)
+
O
2
(
g
)
⟶
2
H
2
O
(
l
)
;
Δ
H
/
k
J
=
−
571.6
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