Calculate the average rms and most probable speed of $S O_{2}$ molecules at $27^{\circ} C$ .

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Solution

Given :

T = 27 + 273
= 300K

$v_{a v g} (S O_{2}) = \sqrt{\frac{8 R T}{π M_{(} S O_{2})}}$

$= \sqrt{\frac{8 \times 0.0821 \times 300}{π \times 64}}$

$= 0.9897 m / s$

$v_{m p s} = \sqrt{\frac{2 R T}{M}}$

$= \sqrt{\frac{2 \times 0.0821 \times 300}{64}}$

$= 0.8773 m / s$

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v_{1} = \sqrt{\frac{x_{1} R T}{M}}

v_{2} = \sqrt{\frac{x_{2} R T}{M}}

v_{3} = \sqrt{\frac{x_{3} R T}{M}}

v_{4} = \sqrt{\frac{x_{4} R T}{M}}

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