Calculate the average velocity of a person in a given time interval if he moves 7m in 4 sec and 18m in 6 sec along the x-axis?

5.5 m / s e c

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9.5 m / s e c

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7.5 m / s e c

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2.5 m / s e c

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Solution

The correct option is B $5.5 m / s e c$
Given,
$s_{1} = 7 m$
$t_{1} = 4 s e c$
$s_{2} = 18 m$
$t_{2} = 6 s e c$
Average velocity,
$v_{a v g} = \frac{s_{2} - s_{1}}{t_{2} - t_{1}}$
$v_{a v g} = \frac{18 - 7}{6 - 4} = \frac{11}{2} = 5.5 m / s e c$
The correct option is A.

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Calculate the average velocity of a person in a given time interval if he moves 7m in 4 sec and 18m in 6 sec along the x-axis?

The correct option is B 5.5m/secGiven,s1=7mt1=4secs2=18mt2=6secAverage velocity,vavg=s2−s1t2−t1vavg=18−76−4=112=5.5m/secThe correct option is A.

The correct option is B $5.5 m / s e c$
Given,
$s_{1} = 7 m$
$t_{1} = 4 s e c$
$s_{2} = 18 m$
$t_{2} = 6 s e c$
Average velocity,
$v_{a v g} = \frac{s_{2} - s_{1}}{t_{2} - t_{1}}$
$v_{a v g} = \frac{18 - 7}{6 - 4} = \frac{11}{2} = 5.5 m / s e c$
The correct option is A.