Question

Calculate the average velocity of Sulphur dioxide molecule at ${427}^{\circ }$C.

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

We know that, Average velocity = $\sqrt{\frac{8RT}{\pi M}}$
M = 64 gm, T = 700K, R = 0.0820 $Latm{K}^{-1}mo{l}^{-1}$
$\sqrt{\frac{8\times 0.0820\times 700}{3.14\times 64}}$ = $\sqrt{2.28}$ =1.50