Question

Calculate the Avogadro's number using the charge on the electron $1.60\times {10}^{-19}$ c and the fact that $96500$ C deposits $107.9$ g silver from its solutions

• A. $5\times {10}^{23}$
• B. $6.225\times {10}^{22}$
• C. $6.03\times {10}^{23}$
• D. $4\times {10}^{23}$

Answer 1

The correct option is C $6.03\times {10}^{23}$

$\begin{array}{c}\text{no. of moles}=\frac{107.9}{107\cdot 9}=1\text{mole}\\ \text{No.of electons in}1\text{mole}=\frac{96500}{1.6\times {10}^{-19}}\\ =\frac{965}{16}\times {10}^{22}\\ =6.03\times {10}^{23}\\ \text{option}c\text{is correct.}\end{array}$