Question

Calculate the binding energy of a deuteron atom, which consists of a proton and a neutron, given that the atomic mass of the deuteron is 2.014102 u

• A. 0.002388 MeV
• B. 2.014102 MeV
• C. 2.16490 MeV
• D. 2.224 MeV

Answer 1

The correct option is D 2.224 MeV

$\begin{array}{c}\text{atomic mass M(H) of hydorgen and nuclear}\\ \text{mass}\left(m_n\right)\text{are}\\ m\left(H\right)=1.007825u\text{and}{M}_n=1.008665u\\ \text{mass defect}\\ \Delta m=\left[M\right(H)+M_n-M(D\left)\right]\end{array}$

$\begin{array}{cc}& 2.016490u-2.014102u\\ \Delta m& =0.002388u\end{array}$

$\begin{array}{c}\text{As 1u correspond to 931.49 Mev energy}\\ \text{therefore mass defect corresponds to}\end{array}$

$\begin{array}{cc}\text{energy}{E}_b& =0.002388\times 931.49\\ & =2.224MeV\\ \text{hence option}D& \text{is correct}\end{array}$