Calculate the binding energy of the oxygen isotope $_{8}^{16} O$ . The mass of the isotope is $16.0 a m u$ .
(Given $e = 0.0005486 a m u$ , $p = 1.00757 a m u$ and $n = 1.00893 a m u$ ).

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Solution

The isotope $_{8}^{16} O$ contains $8$ protons, $8$ neutrons and $8$ electrons.
Actual mass of the nucleus of $_{8}^{16} O = 16 -$ Mass of $8$ electrons
$= 16 - 8 \times 0.0005486 = 159956 a m u$
Mass of the nucleus of $_{8}^{16} O =$ Mass of $8$ protons $+$ Mass of $8$ neutrons
$= 8 \times 1.00757 + 8 \times 1, 00893 = 16.132 a m u$
Mass defect $= (16.132 - 15.9956) = 0.1364 a m u$
Binding energy $= 0.1364 \times 931 = 127 M e V$ .

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